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Two arrows are fired horizontally with the same speed of

30.0m/s. Each arrow has a mass of 0.100 kg. One is fireddue east
and the other due south. Find the magnitude anddirection of the
total momentum of this two-arrow system. Specify the direction with
respect to due east.

1 Answer

3 votes

Answer:

Step-by-step explanation:

Given

mass of each arrow=0.1 kg

velocity of arrow=30 m/s

One arrow is fired u=due to east and another towards south

Momentum of first arrow


P_1=0.1\left ( 30\hat{i}\right )=3\hat{i}


P_2=0.1\left ( -30\hat{j}\right )=-3\hat{j}

Total momentum P


P=P_1+P_2


P=3\hat{i}-3\hat{j}

magnitude
|P|=√(3^2+3^2)=3√(2)

direction


tan\theta =(-3)/(3)


\theta =45^(\circ) clockwise w.r.t to east

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