Answer:
a) 30.726m/s and b) 5.5549s
Explanation:
a.) What was Chris Huber’s speed in meters per second(m/s)?
Given the distance and time, the formula to obtain the speed is
.
Applying this to our problem we have that
.
So, Chris Huber’s speed in meters per second(m/s) was 30.726m/s.
b) What was Whittingham’s time through the 200 m?
In a) we stated that
. This formula implies that
.
First, observer that
.
Then, Sam Whittingham speed was equal to Chris Huber’s speed plus 5.2777 m/s. So,
![v=30.726(m)/(s) +5.2777(m)/(s)= 36.003 m/s.](https://img.qammunity.org/2020/formulas/mathematics/college/45c9cv5m6w5gake4vknvi7m4uvb2detxbt.png)
Then, applying 1) we have that
![t=(200m)/(36.003m/s)=5.5549s.](https://img.qammunity.org/2020/formulas/mathematics/college/ut78q2uzxmie2lz3q61xkd087q6oblmv50.png)
So, Sam Whittingham’s time through the 200 m was 5.5549s.