Question

Thermal conductivity of AISI 316 Stainless Steel at 90ºC is 14.54 W/m K. Convert this value to IP system.

Answer 1

the value of conductivity in IP is
`8.406(Btu)/(ft.hr.F)`

Step-by-step explanation:

Given that

Thermal conductivity K=14.54 W/m.K

This above given conductivity is in SI unit.

SI unit IP unit Conversion factor

m ft 0.3048

W Btu/hr 0.293

The unit of conductivity in IP is Btu./ft.hr.F.

Now convert into IP divided by 1.73 factor.

`0.57(Btu)/(ft.hr.F)=1 (W)/(m.K)`

So

`0.57* 14.54(Btu)/(ft.hr.F)=14.54 (W)/(m.K)`

`8.406(Btu)/(ft.hr.F)=14.54 (W)/(m.K)`

So the value of conductivity in IP is
`8.406(Btu)/(ft.hr.F)`