Question

A slight breeze is blowing over the hot tub above and yields a heat transfer coefficient h of 20 W/m2 -K. The air temperature is 75 F. If the surface area of the hot tub is 7.5 m2 , what is the heat loss (heat rate) due to convection? The temp of Hot Tube is 102F.

Answer 1

Answer:4050 W

Step-by-step explanation:

Given

Heat transfer Coefficient(h)=
`20 W/m^2-K`

Air temperature =75 F

surface area(A)=
`7.5 m^2`

Temperature of hot tube is 102 F

We know heat transfer due to convection is given by

`Q=hA\left ( \Delta T\right )`

`Q=20* 7.5\left ( 102-75\right )=4050 W`