Question

What is the total kinetic energy of a 2500 lbm car when it is moving at 80 mph (in BTU)?

Answer 1

The kinetic energy will be 687.186 BTU

Step-by-step explanation:

We have given mass of car = 2500 lbm

We know that 1 lbm = 0.4535 kg

So 2500 lbm =
`2500* 0.4535=1133.75kg`

Speed = 80 mph

We know that 1 mile = 1609.34 meter

1 hour = 3600 sec

So
`80mph=(80* 1609.34)/(3600)=35.763m/sec`

We know that kinetic energy
`E=(1)/(2)mv^2=(1)/(2)* 1133.75* 35.76^2=725.033KJ`

We know that 1 KJ = 0.9478 BTU

So 725.033 KJ = 725.033×0.9478 = 687.186 BTU