Question

A cable in a motor hoist must lift a 700-lb engine. The steel cable is 0.375in. in diameter. What is the stress in the cable?

Answer 1

Answer:43.70 MPa

Step-by-step explanation:

Given

mass of engine
`700 lb \approx 317.515 kg`

diameter of cable
`0.375 in.\approx 9.525 mm`

`A=(\pi d^2)/(4)=71.26 mm^2`

we know stress(
`\sigma`)
`=(load\ applied)/(area\ of\ cross-section)`

`\sigma =(317.515* 9.81)/(71.26* 10^(-6))=43.70 MPa`