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What is the electric flux through one side of a cube that has a single point charge of-2.80μC placed at its center? Hint: You do not need to integrate any equations to get the answer

User Ahdaniels
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1 Answer

5 votes

Answer:

The flux through one face of a cube is
- 5.2730* 10^(4) Wb

Given:

Charge, Q =
- 2.80\micro C = -2.80* 10^(- 6) C

Solution:

The electric flux,
\phi_(E) = (Q)/(\epsilon_(o))

Since, there are 6 faces in a cube, the flux through one face:


\phi_(E) = (Q)/(6\epsilon_(o))


\phi_(E) = (-2.80* 10^(- 6))/(6\epsilon_(o))


\phi_(E) = - 5.2730* 10^(4) Wb

User Muyueh
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