Question

A mass of 2 kg is hanging to a spring of 200 n/m spring constant vertically. Calculate the period of the period if the spring is set in simple harmonic motion.

Answer 1

The period is 0.628s

Step-by-step explanation:

As the system mass-spring is in simple harmonic motion, the period is given by the equation:

`T=2\pi \sqrt{(m)/(k)}`

where m is the mass of 2kg and k is the spring constant
`200(N)/(m)`

Replacing the values in the equation, we have:

`T=2\pi \sqrt{(2Kg)/(200(N)/(m))}`

And finally we find the value of the period, that is:

`T=0.628s`