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A mass of 2 kg is hanging to a spring of 200 n/m spring constant vertically. Calculate the period of the period if the spring is set in simple harmonic motion.

User Verec
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1 Answer

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Answer:

The period is 0.628s

Step-by-step explanation:

As the system mass-spring is in simple harmonic motion, the period is given by the equation:


T=2\pi \sqrt{(m)/(k)}

where m is the mass of 2kg and k is the spring constant
200(N)/(m)

Replacing the values in the equation, we have:


T=2\pi \sqrt{(2Kg)/(200(N)/(m))}

And finally we find the value of the period, that is:


T=0.628s

User Maxime P
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