Answer:
11.6 mm
Step-by-step explanation:
With a factor of safety of 5 and a yield strength of 900 MPa the admissible stress is:
σadm = strength / fos
σadm = 900 / 5 = 180 MPa
The stress is the load divided by the section:
σ = P / A
σ = 4*P / (π*d^2)
Rearranging:
d^2 = 4*P / (π*σ)
![d = √(4*P / (\pi*\sigma))](https://img.qammunity.org/2020/formulas/engineering/college/ylfp60hiimoagjzg5lty3ykguciqghg7w5.png)
![d = √(4*19000 / (\pi*180*10^6)) = 0.0116 m = 11.6 mm](https://img.qammunity.org/2020/formulas/engineering/college/8ainysqizqhvltb3vh5likscg5awfzahyf.png)