Answer:
Rate of Entropy =210.14 J/K-s
Step-by-step explanation:
given data:
power delivered to input = 350 hp
power delivered to output = 250 hp
temperature of surface = 180°F
rate of entropy is given as
![Rate\ of\ entropy = (Rate\ of \ heat\ released)/(Temperature)](https://img.qammunity.org/2020/formulas/engineering/college/qijux1iuj4cv7ao5rykitrs2zmix375bl4.png)
T = 180°F = 82°C = 355 K
Rate of heat = (350 - 250) hp = 100 hp = 74600 W
Rate of Entropy
![= (74600)/(355) = 210.14 J/K-s](https://img.qammunity.org/2020/formulas/engineering/college/qcusb51d7bmq22rcpwew24w5hqs7175kjv.png)