Answer:
11.125°
Step-by-step explanation:
Given:
Radius of bend, R = 100 m
Speed around the bend = 50 Km/hr =
= 13.89 m/s
Now,
We have the relation

where,
θ = angle of banking
g is the acceleration due to gravity
on substituting the respective values, we get

or

or
θ = 11.125°