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Air flows at 45m/s through a right angle pipe bend with a constant diameter of 2cm. What is the overall force required to keep the pipe bend in place? Is it: a) 0.76 N b) 1.08 N c) 1.52 N d) 0.25 N e) 2.56 N

1 Answer

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Answer:

b)1.08 N

Step-by-step explanation:

Given that

velocity of air V= 45 m/s

Diameter of pipe = 2 cm

Force exerted by fluid F


F=\rho AV^2

So force exerted in x-direction


F_x=\rho AV^2


F_x=1.2* (\pi)/(4)* 0.02^2* 45^2

F=0.763 N

So force exerted in y-direction


F_y=\rho AV^2


F_y=1.2* (\pi)/(4)* 0.02^2* 45^2

F=0.763 N

So the resultant force R


R=√(F_x^2+F_y^2)


R=√(0.763^2+0.763^2)

R=1.079

So the force required to hold the pipe is 1.08 N.

User Tobias Etter
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