Question

A 4-kg-plastic tank that has a volume of 0.2 m^3 is filled with liquid water. Assuming the density of water is 1000 kg/m^3, determine the weight the combined system.

Answer 1

The weight of the combined system is 2001.24 Newtons

Step-by-step explanation:

From the basic relation between mass, density and volume we know that

`density=(Mass)/(Volume)`

In our context we are given that the density of water is 1000 kg per cubic meters

Thus we can find the mass of 0.2 cubic meters of water using the above relation as

`1000kg/m^(3)=(Mass)/(0.2m^(3))\\\\\therefore Mass=1000kg/m^(3)* 0.2m^(3)=200kg`

Hence the mass of water in the tank is 200 kilograms.

The total mass of water and the plastic tank thus becomes

`200+4=204kg`

Now we know that weight of any given mass is calculated as

`Weight=mass\g`

where,

'g' is the acceleration due to gravity with value =
`9.81m/s^(2)`

Applying the values in the above equation we get

`Weight=204* 9.81=2001.24Newtons`