Answer:

Approximate error = 0.4426
Explanation:
f(x)=tanx, a=0
Maclaurin series formula used is given below

f(x)=tanx
f(0)=tan0=0




Hence, the Taylor series for f(x)=tanx is given by

Maclaurin series upper bound error formula used is given as
R_n(x)=|f(x)-T_n(x)|
R_3(x)=|tanx-T_3(x)|

Plugging this value x=1

R_3(x)=|1.5574-1-0.333-0.666|
R_3(x)=|-0.4426|=0.4426
Hence, upper bound on the error approximation
tan(1)=0.4426