Answer:
In order to have a consistent linear system represented by the augmented matrix:
![\left[\begin{array}{ccc}2&-3&h\\-6&9&5\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/college/p8ih490pzj21p3wcig6rnzipj6o9j1nj9d.png)
the value of h must be:
![h=-(5)/(3)](https://img.qammunity.org/2020/formulas/mathematics/college/7ql4nj0mly67tim1jrmawadw706hdjjlrb.png)
Explanation:
A system is consistent if it has a solution, this solution can be unique or a set of infinite solutions.
First, you take the augmented matrix and find the equivalent row echelon form using Gaussian-Jordan elimination:
To do this, you have to multiply the 1st row by 3 and add it to the 2nd row, the resulting matrix is:
![\left[\begin{array}{ccc}2&-3&h\\0&0&5+3h\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/college/miycwje7la7l9lxl09x71zp8jg22w3m80k.png)
Now, write the system of equations:
![2x_1-3x_2=h\\0x_1+0x_2=5+3h](https://img.qammunity.org/2020/formulas/mathematics/college/7yiv29bmj02ouvyjj092o23gzhyzy5o5vr.png)
The only way this system has a solution is if 5+3h=0, then, to satisfy this, the value of h must be:
![h=-(5)/(3)](https://img.qammunity.org/2020/formulas/mathematics/college/7ql4nj0mly67tim1jrmawadw706hdjjlrb.png)