Question

A circular piston exerts a pressure of 80kPa on a fluid

whenthe force applied to the piston is 0.2kN . Find the diameter of
thepiston.

Answer 1

Diameter of the piston will be
`3.1847* 10^(-3)m`

Step-by-step explanation:

We have given force F = 0.2 kN = 200 N

Pressure P = 80 kPa = 80000 pa

We have to find the diameter of the piston

We know that
`pressure = (force)/(area )=(200)/(80000)=2.5* 10^(-3)m^2`

We know that area of circular piston is given by
`A=\pi r^2`

So
`2.5* 10^(-3)=3.14* r^2`

`r=1.5923* 10^(-3)m`

We know that diameter d = 2×radius =
`d=1.5923* 10^(-3)* 2=3.1847* 10^(-3)m`