Answer:
The velocity of the fluid is 1.1012 m/s
Solution:
As per the question, for the fluid:
Diameter of the capillary tube, d = 1.0 mm =
![1.0* 10^(- 3) m](https://img.qammunity.org/2020/formulas/engineering/college/8f4r2kvpb3b2bm2hvr34s7z1ss8ivczjfh.png)
Reynolds No., R = 1000
Kinematic viscosity,
![\mu_(k) = 1.1012* 10^(- 6) m^(2)/s](https://img.qammunity.org/2020/formulas/engineering/college/xbmqgyzjc2zh7s60sa9zdfy582uwgd2zwi.png)
Now, for the fluid velocity, we use the relation:
![R = (v_(f)* d)/(\mu_(k))](https://img.qammunity.org/2020/formulas/engineering/college/pztl8uk7gc9qb7s5bc7tful48ywgailu4t.png)
where
= velocity of fluid
![v_(f) = (R* \mu_(k))/(d)](https://img.qammunity.org/2020/formulas/engineering/college/1pslgzlo6dr3wtdzrhaaue5vdzrjh8nbnz.png)
![v_(f) = (1000* 1.1012* 10^(- 6))/(1.0* 10^(- 3)) = 1.1012 m/s](https://img.qammunity.org/2020/formulas/engineering/college/6gsi0d5tcywzriys631vapa0k5jn1usiip.png)