Question

A piston moves a 25kg hammerhead vertically down 1m from rest to a

velocity of 50m/s in a stamping machine.

what is the total change in energy of the hammerhead?

Answer 1

Change in energy will be 31.25 KJ

Step-by-step explanation:

We have given mass of the piston = 25 kg

Initial velocity u = 0 m/sec

Final velocity v = 50 m/sec

Kinetic energy is given by
`KE=(1)/(2)mv^2`

We have to find the change in energy

So change in energy = final KE - initial KE

`\Delta E=(1)/(2)m(v^2-u^2)`

`\Delta E=(1)/(2)25* (50^2-0^2)=31250j=31.25KJ`

So change in energy will be 31.25 KJ

Answer 2

Total change in energy = 31 KJ.

Step-by-step explanation:

Mass m=25 kg

Height h = 1 m

Initial velocity = 0

Final velocity = 50 m/s

Energy at initial condition

`E_1=mgh+(1)/(2)mv^2`

`E_1=25* 10* 1+0`

`E_1=250\ J`

Energy at final condition

`E_2=0+(1)/(2)* 25* 50^2`

`E_2=31250\ J`

So the change in energy = 31250 -250 J

The total change in energy = 31000 J