Answer:
Lee has more pizza
Lee has 2.24 in^2 more than John
Step-by-step explanation:
step 1
Find the area of each slice of pizza

we have
----> the radius is half the diameter
substitute


step 2
Find the area of John's part (area of shaded triangle)
The measure of the central angle of each slice of pizza is equal to

so
the height of triangle is equal to the base
Let
x ---->the base of the shaded triangle


Remember that

substitute

solve for x

Find the area of shaded triangle

step 3
Find the area of Lee's part
The area of Lee's part is equal to the area of two slices of pizza minus the area of two triangles
so

assume


so
Lee's part is greater than John part's
Find the difference

therefore
Lee has more pizza
Lee has 2.24 in^2 more than John