Answer:
![4.5 \text{ miles per gallon}](https://img.qammunity.org/2020/formulas/mathematics/college/8m8f7e0elbxo88dvw7x5v857x48f5csq9o.png)
Explanation:
Given : The fuel efficiency of car = 7.6 km per kilogram
We also given that
1 mile = 1.609 km
Then,
![\text{1 km}=(1)/(0.609)\text{ mile}](https://img.qammunity.org/2020/formulas/mathematics/college/vq64x3y16eucih64660ourdoeusebzmsgp.png)
1 gallon = 3.785 liters
![\text{1 liter}=(1)/(3.785)\text{ gallon}](https://img.qammunity.org/2020/formulas/mathematics/college/f2ybdrvdcguxdvg3sdbz8fyxgpwnlmt8w9.png)
1 liter of gasoline = 0.729 kg
Then,
![\text{1 kg}=(1)/(0.729)\text{ liter}](https://img.qammunity.org/2020/formulas/mathematics/college/98vqoqi1n5l2hbk5jfv6v9ubpui6uscuh8.png)
![\Rightarrow\ \text{1 kg}=(1)/(0.729)*(1)/(3.785)\text{gallon}](https://img.qammunity.org/2020/formulas/mathematics/college/wyizi5fuyjt5hw93hlpmzx3mrq0tc5xemb.png)
Now, the fuel efficiency of car will be :
![7.6*(1)/(0.729)*(1)/(3.785)*(1)/(0.609)\\\\=4.52275317827\approx4.5 \text{ miles per gallon}](https://img.qammunity.org/2020/formulas/mathematics/college/wttkw1mpyfauvhndb7bui6t8wdajocqms8.png)
Hence, the car’s fuel efficiency in miles per gallon= 4.5