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The data from an independent-measures research study produce a sample mean difference of 4 points and a pooled variance of 18. If there are n = 4 scores in each sample, what is the estimated standard error for the sample mean difference?​

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Answer: 3

Explanation:

Given : Pooled variance :
\sigma^2=18

Sample sizes of each sample =
n_1=n_2=4

We know that the standard error for the sample mean difference is given by :-


S.E.=\sqrt{\sigma^2((1)/(n_1)+(1)/(n_2))}\\\\=\sqrt{(18)((1)/(4)+(1)/(4))}\\\\=\sqrt{(18)((1)/(2))}=√(9)=3

Hence, the estimated standard error for the sample mean difference =3

User Leszek Mazur
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