Answer:
0.0567 N
Step-by-step explanation:
q1 = 3 micro coulomb
q2 = - 2 micro coulomb
OB = 50 cm
AB = 60 cm
By using Pythagoras theorem in triangle OAB


OA = 78.1 cm
By using the Coulomb's law, the force on 3 micro coulomb due to -2 micro coulomb is

F = 0.0885 N
The horizontal component of force is
= F CosФ =

= 0.0885 x 50 / 78.1 = 0.0567 N