Question

A test specimen in a tensile test has a gage length of 2.0 in and an area = 0.5in^2. During the test the specimen yields under a load of 32,000 lb. The corresponding gage length = 2.0083 in. This is the 0.2% yield point. The maximum load of 60,000 lb is reached at a gage length = 2.6 in. Determine a) yield strength, b) madulus of elasticity, and c) ten

Answer 1

yield strength is 64000 lb/ in²

modulus of elasticity is 29.76 ×
`10^(6)` lb/in²

Step-by-step explanation:

given data

length L = 2 in

area A = 0.5 in²

load = 32000 lb

gage length L1 = 2.0083 in

yield point = 0.2%

maximum load = 60000 lb

to find out

yield strength and modulus of elasticity

solution

we apply here yield strength that is express as

yield strength =
`(load)/(area)` ...........1

yield strength =
`(32000)/(0.5)`

yield strength = 64000 lb/ in²

and

modulus of elasticity is calculated as

modulus of elasticity =
`(yield strength)/(strain)` ..........2

here strain =
`(L1 - L)/(L)`

strain =
`(2.0083 - 2)/(2)`

strain = 0.00415

so new strain after offset is here 0.00415 - 0.002

new strain = 0.00215

so from equation 2

modulus of elasticity =
`(yield strength)/(strain)`

modulus of elasticity =
`(64000)/(0.00215)`

modulus of elasticity is 29.76 ×
`10^(6)` lb/in²