Question

If a glass is knocked off of a table that is 2.6 m tall, how long does it take for the glass to hit the ground? FILL IN All GUESS STEPS TO GET CREDIT. CHECK EXAMPLE PROBLEM BELOW.

Answer 1

0.73 sec

Step-by-step explanation:

formula:X=ViT+(0.5)AT^2

2.6=(0)T+(0.5)(9.8)T^2

cancel:(0)T

2.6=(0.5)(9.8)T^2

take 0.5 to other side and divide with 2.6

5.2=(9.8)T^2

now do the same with 9.8

0.530612 and square root it because u can't leave the T^2

you'll get t=0.73 s

Answer 2

0.73 s

Step-by-step explanation:

The glass is in free fall, so its vertical position at time t is given by the equation:

`y(t) = h + ut + (1)/(2)gt^2`

where

h = 2.6 m is the initial height

u = 0 is the initial velocity of the glass

`g=-9.8 m/s^2` is the acceleration of gravity (downward since it is negative)

We want to know the time t at which the glass reaches the ground, so when

y(t) = 0

So the equation becomes

`0 = h + (1)/(2)gt^2`

And solving for t, we find

`t=\sqrt{(-2h)/(g)}=\sqrt{(-2(2.6))/(-9.8)}=0.73 s`