Question

A nervous squirrel gets startled and runs 5.0\,\text m5.0m5, point, 0, space, m leftward to a nearby tree. The squirrel runs for 0.50\,\text s0.50s0, point, 50, space, s with constant acceleration, and its final speed is 15.0\,\dfrac{\text m}{\text s}15.0 s m ​ 15, point, 0, space, start fraction, m, divided by, s, end fraction. What was the squirrel's initial velocity before getting startled

Answer 1

−5.0

Step-by-step explanation:

Answer 2

The squirrel's initial velocity is 5 m/s.

Step-by-step explanation:

It is given that,

Distance covered by the squirrel, d = 5 m

Time taken, t = 0.5 s

Final speed of the squirrel, v = 15 m/s

To find,

The squirrel's initial velocity.

Solution,

Let a is the acceleration of the squirrel. Using the first equation of motion to find it :

`a=(v-u)/(t)`

`a=(15-u)/(0.5)`..............(1)

Let u is the initial speed of the squirrel. Using again third equation of kinematics to find it :

`v^2-u^2=2ad`

Use equation (1) to put value of a

`(15)^2-u^2=2* (15-u)/(0.5)* 5`

`225-u^2=20(15-u)`

On solving the above quadratic equation, we get the value of u as :

u = 5 m/s

Therefore, the squirrel's initial velocity before getting started is 5 m/s.