Question

A ball of mass 0.16 kg is moving forwards at a speed of 0.50 m/s. A second ball of mass 0.10kg is stationary. The first ball strikes the second ball. The second ball moves forwards at a speed of

0.50 m/s.
What is the speed of the first ball after the collision?​

Answer 1

0.19 m/s

Step-by-step explanation:

Momentum before collision = momentum after collision

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

(0.16 kg) (0.50 m/s) + (0.10 kg) (0 m/s) = (0.16 kg) v₁ + (0.10 kg) (0.50 m/s)

0.08 kg m/s = (0.16 kg) v₁ + 0.05 kg m/s

0.03 kg m/s = (0.16 kg) v₁

v₁ ≈ 0.19 m/s