Question

A line passes through (0, –7) and has a slope of -2/3. What is the equation of the line in slope-intercept form

Answer 1

the required equation is y = ( -2/3 )x -7

Explanation:

Given :-

the line passes through the point ( 0 , -7 )

)and slope of the line is ( -2/3 )

• To form an equation when one point and it's slope is given ,

• To form an equation when one point and it's slope is given , we use ;

• To form an equation when one point and it's slope is given , we use ;( y - y1 ) = m ( x - x1 )

• To form an equation when one point and it's slope is given , we use ;( y - y1 ) = m ( x - x1 )Where , x and y are variables

• To form an equation when one point and it's slope is given , we use ;( y - y1 ) = m ( x - x1 )Where , x and y are variablesand x1 and y1 are the points where the line meet !

• To form an equation when one point and it's slope is given , we use ;( y - y1 ) = m ( x - x1 )Where , x and y are variablesand x1 and y1 are the points where the line meet ! and m is slope of the tangent !!

y1 = -7

x1 = 0

So, putting all the values in the equation we get ,

`(y - ( - 7)) = (( -2 ))/(3) (x - 0) \\ \\ y + 7 = ( - 2)/(3) x \\ \\ 3y + 21 = - 2x \\ \\ 3y = - 2x - 21`

`3y = - 21 - 2x \\ \\ y = ( - 2)/(3) x - (21)/(3 ) \\ \\ y = ( - 2)/(3) x - 7`

• Slope intercept form of the equation

• Slope intercept form of the equation y = mx + c

• Slope intercept form of the equation y = mx + c Where , m is slope of the line

• Slope intercept form of the equation y = mx + c Where , m is slope of the line and c is y intercept !!

[ also , we can directly put the value of c = -7 and m = ( -2/3 ) from given ]

Hence , here m = (-2/3 ) and c = -7

So, the required equation is y = ( -2/3 )x -7