Question

A car travels in the +x-direction on a straight and level road. For the first 3.00 s of its motion, the average velocity of the car is υav−x = 6.31 m/s .

How far does the car travel in 4.00s?

Answer 1

25.24 m

Step-by-step explanation:

We are given that a car travels in the positive x direction on a straight and level road.

We have to find the distance travel by car in 4 s.

Average velocity of car=6.31 m/s

Time =3 s

Distance traveled by the car in 3 sec=
`velocity* time`

Distance traveled by the car in 3 sec=
`6.31* 3=18.93 m`

Distance traveled by the car in 1 sec=6.93 m

Distance traveled by the car in 4 sec=
`6.93* 4=25.24 m`

Hence,distance traveled by the car in 4 sec=25.24 m