Question

The length I of a rectangle is twice its width.The perimeter is 60 ft.find it area

Answer 1

A = 200ft²

Info:

l = 2w

P=2[(2w)+w)

P = 60

A=w(2w)

Explanation:

Since we know the value of the perimeter, it's actually easy to solve with the information listed above.

Firstly, since the equation has the same variable, you can actually add them or multiply. You can write the perimeter in a new way,

P=6w

which means w =
`(p)/(6)`,
`(60)/(6)` or 10ft.

Now we know the width you can get the length by multiplying it by 2. Let's get the rectangle area.

A=w(2w) or A=wl

A=10(2x10) or A=10(20)

A = 200ft²