Answer:
the charge the photoelectric effect induce is 0.132 × 10⁻¹¹ C
Step-by-step explanation:
energy of ultraviolet light =
![(hc)/(\lambda)](https://img.qammunity.org/2020/formulas/physics/college/xpt8qb222lgesxlya5owvr3h9ha6ld56gn.png)
=
![(6.626 * 10^(-34)* 3 * 10^8)/(251* 10^(-9))](https://img.qammunity.org/2020/formulas/physics/college/hoscha6udxdcjbprulxbvnx6qg6ml576dv.png)
=7.91 × 10⁻¹⁹ J
=4.94 e V
energy released by the electron = 4.94 - 4.70
= 0.24 e V
potential at the surface of sphere =
![(K Q)/(r)](https://img.qammunity.org/2020/formulas/physics/college/5flw9z0rhz042lc03zjua6bpt60znzhh7o.png)
0.24 =
![(9* 10^9* Q)/(0.0495)](https://img.qammunity.org/2020/formulas/physics/college/r05dn9gux8samo1m0dsgs11iqbtb0ue8i6.png)
Q = 0.132 × 10⁻¹¹ C
hence, the charge the photoelectric effect induce is 0.132 × 10⁻¹¹ C