Question

Light passes from a material A, which has an index of refraction of 4/3, into material B, which has an index of refraction of 5/4. If the angle of incidence is 30°, what is the angle of refraction? (a) 14.1° (b) 32.2° (C) 28.4° (d) 46.0° (e) 51.0°

Answer 1

(b) 32.2°

Step-by-step explanation:

Using Snell's law as:

`n_i* {sin\theta_i}={n_r}*{sin\theta_r}`

Where,

`{\theta_i}` is the angle of incidence ( 30.0° )

`{\theta_r}` is the angle of refraction ( ? )

`{n_r}` is the refractive index of the refraction medium (Material B, n=5 / 4)

`{n_i}` is the refractive index of the incidence medium (Material A, n=4 / 3)

Hence,

`{\frac {4}{3}}* {sin30.0^0}={\frac {5}{4}}*{sin\theta_r}`

Angle of refraction =
`sin^(-1)0.5333` = 32.2°