Question

The human ear canal is about 2.3 cm long. If it is regarded as a tube open at one end and closed at the eardrum, what is the fundamental frequency around which we would expect hearing to be most sensitive?

Answer 1

For the given conditions the fundamental frequency is 3728.26 Hertz

Step-by-step explanation:

We know that for a pipe open at one end and closed at other end the fundamental frequency is given by

`f=(V_(s))/(4L)`

where

f is the fundamental frequency

`V_(s)` is the speed of sound in air in the surrounding conditions.

L = Length of the pipe

Applying values we get and using speed of sound as 343m/s we get

`f=(343)/(4* 2.3* 10^(-2))=3728.26Hz`