Answer:
The force at a distance of 3.66 cm from
will be zero
Step-by-step explanation:
Electric force experienced will be zero where electric field will be zero .
We have given charges
![q_1\ and\ q_2=3q_1](https://img.qammunity.org/2020/formulas/physics/college/a9bfx6ulzre26xmma4sl9k2amufk9ji2mu.png)
Distance between the charges = 10 cm
Let at d distance from q_1 electric field will be zero , so distance from q_2 =10-d
According to coulombs law electric field is given by
![E=(KQ)/(R^2)](https://img.qammunity.org/2020/formulas/physics/college/ih8sp8tsfjre32lxgf20bxhqh8v2lau153.png)
![(Kq_1)/(d^2)=(K3q_1)/((10-d)^2)](https://img.qammunity.org/2020/formulas/physics/college/8rmyrc8h01fbakl67p1mw911yayfk8skwp.png)
![((10-d))/(d)=\sqrt{(3q_1)/(q_1)}](https://img.qammunity.org/2020/formulas/physics/college/jxqc6zxpzkw5mcrw0khi15tdvfqm0f5kcu.png)
![10-d=1.732d](https://img.qammunity.org/2020/formulas/physics/college/ft0mn8m8de8q1c8mlz35e06mo5l3vst0fx.png)
d = 3.66 cm
So the force at a distance of 3.66 cm from
will be zero