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Two positively charged particles q1 and q2 = 3q1 are 10.0 cm apart. Where (other than at infinity) could a third charge q3 be placed so as to experience no net electric interaction?

User Ahmad Mayo
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1 Answer

3 votes

Answer:

The force at a distance of 3.66 cm from
q_1 will be zero

Step-by-step explanation:

Electric force experienced will be zero where electric field will be zero .

We have given charges
q_1\ and\ q_2=3q_1

Distance between the charges = 10 cm

Let at d distance from q_1 electric field will be zero , so distance from q_2 =10-d

According to coulombs law electric field is given by


E=(KQ)/(R^2)


(Kq_1)/(d^2)=(K3q_1)/((10-d)^2)


((10-d))/(d)=\sqrt{(3q_1)/(q_1)}


10-d=1.732d

d = 3.66 cm

So the force at a distance of 3.66 cm from
q_1 will be zero

User Kaela
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