Answer:
l = 0.8 m
gMars = 3.65 m/s2
Step-by-step explanation:
The period of a pendulum depends on the length of it and the acceleration of gravity according to this equation:
![T = 2 \pi \sqrt{(l)/(g)}](https://img.qammunity.org/2020/formulas/physics/college/qy4myl7sr899pk091p112d0a73n9oqplph.png)
If the pendulum has a period of 1.8s on Earth, the length must be:
![l = g * ((T)/(2\pi))^2 = 9.81 * ((1.8)/(2\pi))^2 = 0.8 m](https://img.qammunity.org/2020/formulas/physics/college/ocgoctmy5q7uiec2dp6a9337yfpx0k9pbq.png)
If it has a period of 2.94 s on Mars, the gravity must be:
![g = (l)/(((T)/(2\pi))^2) = (4 \pi^2 l)/(T^2) = (4 \pi^2 * 0.8)/(2.94^2) = 3.65 (m)/(s^2)](https://img.qammunity.org/2020/formulas/physics/college/aenii92hsmh82u7f3x7gsi7hwkookdy202.png)