Answer:
![\dot m = 2.74 kg/s](https://img.qammunity.org/2020/formulas/engineering/college/u5uwowkaqr55f9m10wgw97sjjole54lgey.png)
Step-by-step explanation:
given data:
pressure 1 MPa
diameter of pipe = 30 cm
average velocity = 10 m/s
area of pipe
![= \frac[\pi}{4}d^2](https://img.qammunity.org/2020/formulas/engineering/college/r3f6ptjivdtala08fub8su9df30i87x9xt.png)
![= (\pi)/(4) 0.3^2](https://img.qammunity.org/2020/formulas/engineering/college/pu4fv8fz64yovg96io2zpidfcw2q4tl6qa.png)
A = 0.070 m2
WE KNOW THAT mass flow rate is given as
![\dot m = \rho A v](https://img.qammunity.org/2020/formulas/engineering/college/1y2hvxx8ywax5hu760hu9rgqcz3vhturwo.png)
for pressure 1 MPa, the density of steam is = 4.068 kg/m3
therefore we have
![\dot m = 4.068 * 0.070* 10](https://img.qammunity.org/2020/formulas/engineering/college/6r798jgf67n4j0sdywld011phtk5mm50i9.png)
![\dot m = 2.74 kg/s](https://img.qammunity.org/2020/formulas/engineering/college/u5uwowkaqr55f9m10wgw97sjjole54lgey.png)