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A Boeing 747 "Jumbo Jet" has a length of 59.7 m. The runway on which the plane lands intersects another runway. The width of the intersection is 25.0 m. The plane decelerates through the intersection at a rate of 5.4 m/s2 and clears it with a final speed of 53 m/s. How much time is needed for the plane to clear the intersection?

1 Answer

4 votes

Answer:

t = 1.48 s

Step-by-step explanation:

As we know that length of the Boeing plane is


L = 59.7 m

width of the intersection is given as


w = 25.0 m

now we know that deceleration of the plane is given as


a = -5.4 m/s^2

Also the final speed of the plane while it clears the intersection is given as


v_f = 53 m/s

now we have


d = ((v_f + v_i)/(2)) t


(25 + 59.7) = ((53 + v_i)/(2)) t

also we know that


v_f - v_i = at


53 - v_i = -5.4 t

now we have


84.7 = ((53 + 53 + 5.4t)/(2))t

by solving above equation we have


t = 1.48 s

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