Answer:
Option B
Step-by-step explanation:
A father genotype for male sexuality is X'Y
Since he possess an X - linked disorder, thus in case if it is crossed with a mother with XX genotype
Thus, X'Y * XX
X'X, X'X, XY, XY
Thus, it is clear that a male child will carry Y chromosomes from his father and X chromosome from her mother. Thus, in order to have X-linked disorder, the male child must receive an affected X allele from his mother.
Hence, the probability of son inheriting an X-linked disorder from his father would be zero.
Option B is correct