Question

A freighter carrying a cargo of uranium hexafluoride sank in the English Channel in late August 1984. The cargo of uranium hexafluoride weighed 2.25 x 108 kg and was contained in 30 drums, each having a volume of 1.62 x 106 L. What is the density (g/mL) of uranium hexafluoride?

Answer 1

`\rho = 4.63 g/mL`

Step-by-step explanation:

Volume of each drum in which the Uranium Hexafluoride is contained is given as

`V = 1.62 * 10^6 L`

`V = 1.62 * 10^9 mL`

now we know that mass of the uranium is given as

`m = 2.25 * 10^8 kg`

now total volume of all 30 containers is given as

`V = 30 (1.62 * 10^9)`

`V = 4.86 * 10^(10) mL`

`m = 2.25 * 10^(11) g`

so now the density is given as

`\rho = (m)/(V)`

`\rho = (2.25 * 10^(11))/(4.86 * 10^(10))`

`\rho = 4.63 g/mL`