Question

The barrel of a rifle has a length of 0.89 m. A bullet leaves the muzzle of a rifle with a speed of 620 m/s. What is the acceleration of the bullet while in the barrel? A bullet in a rifle barrel does not have constant acceleration, but constant acceleration is to be assumed for this problem.

Answer 1

The muzzle velocity of the bullet when it leaves the barrel is approximately 0.502 m/s.

Step-by-step explanation:

The acceleration of the bullet while in the barrel can be calculated using the average rate of acceleration and the time taken. The given average acceleration is 6.20 × 105 m/s² and the time is 8.10 × 10-4 s. To find the acceleration, we can use the formula:

a = (vf - vi) / t

Where 'vf' is the final velocity, 'vi' is the initial velocity, and 't' is the time taken.

Since the bullet starts from rest in the barrel, the initial velocity 'vi' is 0 m/s. Plugging in the values:

a = (vf - 0) / (8.10 × 10-4)

Simplifying the equation:

a = vf / (8.10 × 10-4)

Now, we can solve for 'vf', which is the muzzle velocity (final velocity) of the bullet:

vf = a * (8.10 × 10-4)

Substituting the given acceleration value:

vf = 620 m/s * (8.10 × 10-4)

Calculating the result:

vf ≈ 0.502 m/s

Therefore, the muzzle velocity of the bullet when it leaves the barrel is approximately 0.502 m/s.