Answer:
a) 0.975 m
b) 13.25 m
Step-by-step explanation:
given data:
pressure gage reading 130 kPa
a) mercury with density 13,600 kg/m^3
let distance between two fluid level is h,
then
we know that
![p = \rho g h](https://img.qammunity.org/2020/formulas/engineering/college/9t1jqozb2tgakokcx2s3ag4bpzyxl1zneu.png)
13600*9.8*h=130*10^3
so h = 0.975 m
b.) water with density 1000 kg/m^3
let distance between two fluid level is h,
then
we know that
![p = \rho g h](https://img.qammunity.org/2020/formulas/engineering/college/9t1jqozb2tgakokcx2s3ag4bpzyxl1zneu.png)
1000*9.8*h= 130*10^3
so h= 13.25 m