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Calculate the ratio of the mass ratio of S to O in SO to the mass ratio of S to O in SO2.Estimate that the mass of S = 32 g and the mass of O = 16 g for this experiment. That is, the experimenter has enough sample such that there are 32 g of S in each.

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Answer: The ratio of the mass ratio of S to O in SO to the mass ratio of S to O in
SO_2 is 2.

Step-by-step explanation:

We are given:

Mass of sulfur = 32 grams

Mass of oxygen = 16 grams

  • Taking SO molecule:

A chemical compound having a chemical formula of SO

Mass of Sulfur in SO = 32 g

Mass of Oxygen in SO = 16 g

Mass ratio of Sulfur to oxygen in SO =
\frac{\text{Mass of sulfur}}{\text{Mass of oxygen}}=(32g)/(16g)=2 .....(1)

  • Taking
    SO_2 molecule:

A chemical compound having a chemical formula of
SO_2

Mass of Sulfur in
SO_2 = 32 g

Mass of Oxygen in
SO_2 = (2 × 16) = 32 g

Mass ratio of Sulfur to oxygen in
SO_2 =
\frac{\text{Mass of sulfur}}{\text{Mass of oxygen}}=(32g)/(32g)=1 .....(2)

Taking ratio of 1 and 2, we get:


\frac{\text{Mass ratio of Sulfur to oxygen in SO}}{\text{Mass ratio of Sulfur to oxygen in }SO_2}=(2)/(1)=2

Hence, the ratio of the mass ratio of S to O in SO to the mass ratio of S to O in
SO_2 is 2.

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