Register
In 1990 Walter Arfeuille of Belgium lifted a 281.5-kg object through a distance of 17.1 cm using only his teeth. (a) How much work did Arfeuille do on the object?
87.8k views
1 vote
In 1990 Walter Arfeuille of Belgium lifted a 281.5-kg object through a distance of 17.1 cm using only his teeth. (a) How much work did Arfeuille do on the object?

User Charlietfl
by
5.4k points

1 Answer

4 votes

Answer:

Work done, W = 471.73 Joules

Step-by-step explanation:

It is given that,

Mass of an object, m = 281.5 kg

Distance covered by the object, d = 17.1 cm = 0.171 m

We need to find the work done by Arfeuille on the object. The work done is given by :


W=F* d


W=m* g* d


W=281.5* 9.8* 0.171

W = 471.73 J

So, the work done by Arfeuille on the object is 471.73 Joules. Hence, this is the required solution.

User Squiroid
by
5.1k points
Ask a Question
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

5.2m questions

6.8m answers

Other Questions

A space shuttle is approaching the surface of the moon to land. It approaches the moons surface with an initial velocity of 28m/s and is slowing at a rate of -2m/s^2. Show all work and units for problems.
________ is a measure of the internal energy that has been absorbed or transferred from one body to another, often due to a difference in temperature.
5. What happens to the arrangement of water molecules as ice melts? A Molecules gain enough energy to escape as vapor. B Molecules release enough energy to escape as vapor. C Molecules gain enough energy
A projectline is shot from the edge of a cliff 100 m above the ground with intial speed 10 m/s at an angle 30 with the horizontal. 1) determine the time taken by the projectile motion to hit the ground
You’re on a team performing a high-magnetic-field experiment. A conducting bar carrying 4.1 kA will pass through a 1.3-m-long region containing a 12-T magnetic field, making a 60° angle with the field.
Link Copied!