Question

In 1990 Walter Arfeuille of Belgium lifted a 281.5-kg object through a distance of 17.1 cm using only his teeth. (a) How much work did Arfeuille do on the object?

Answer 1

Work done, W = 471.73 Joules

Step-by-step explanation:

It is given that,

Mass of an object, m = 281.5 kg

Distance covered by the object, d = 17.1 cm = 0.171 m

We need to find the work done by Arfeuille on the object. The work done is given by :

`W=F* d`

`W=m* g* d`

`W=281.5* 9.8* 0.171`

W = 471.73 J

So, the work done by Arfeuille on the object is 471.73 Joules. Hence, this is the required solution.