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If a particle's position is given by x=4-12t+3t^2, where t is in seconds and x is in meters, what is its velocity at t=1 second?

If a particle's position is given by x=4-12t+3t^2, where t is in seconds and x is in meters, what is its velocity at t=1 second?
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If a particle's position is given by x=4-12t+3t^2, where t is in seconds and x is in meters, what is its velocity at t=1 second?

User Andreas Sauer
by
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1 Answer

2 votes

Answer:

v = -6m/s

Step-by-step explanation:


x=4-12t+3t^2


(dx)/(dt)=-12+6t

For t = 1:


(dx)/(dt)=-6

User Samshull
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