Question

If a particle's position is given by x=4-12t+3t^2, where t is in seconds and x is in meters, what is its velocity at t=1 second?

Answer 1

v = -6m/s

Step-by-step explanation:

`x=4-12t+3t^2`

`(dx)/(dt)=-12+6t`

For t = 1:

`(dx)/(dt)=-6`