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Automotive air bags inflate when a sample of Sodium Azide NaN3 is very rapidly decomposed.

2NaN3 ? 2Na +3N2
what mass of Sodium Azide is required to produce 2.6 feet3 (736 L) of Nitrogen gas with the density of 1.25 g/L?

User Cordsen
by
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2 Answers

0 votes

Answer:

141 g

Step-by-step explanation:

User Randy Syring
by
5.2k points
6 votes

Answer: 1424 grams

Step-by-step explanation:


2NaN_3\rightarrow 2a+3N_2


Density=(mass)/(Volume)


1.25g/L=(mass)/(736L)


Mass=920g

Thus mass of nitrogen produced is 920 g.


\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}


\text{Number of moles of nitrogen}=(920g)/(28g/mol)=32.8moles

According to stoichiometry:

3 mole of
N_2 are produced from= 2 mole of
NaN_3

Thus 32.8 moles of
N_2 are produced from=
(2)/(3)* 32.8=21.9moles of
NaN_3

Mass of
NaN_3=moles* {\text {molar mass}}=21.9* 65=1424g

Thus 1424 grams of sodium azide is required to produce 736 L of Nitrogen gas with the density of 1.25 g/L.

User Dronz
by
5.3k points