Answer:
The largest angle of the quadrilateral is 120°.
Explanation:
Given : The ratio of three consecutive angles in a cyclic quadrilateral is 2:3:4
To find : The largest angle of the quadrilateral, in degrees ?
Solution :
Let the ration be 'x',
So, The consecutive angles are 2x , 3x and 4x.
We know that, Opposite angles of cyclic quadrilateral is 180°.
i.e.
![2x+4x=180](https://img.qammunity.org/2020/formulas/mathematics/high-school/elvc2l5q5ggs8kaxxoz9qsjde7xzzlbeuw.png)
![6x=180](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hl1ofz2466u9w6njo8v8cgrfx1qx01gggy.png)
![x=(180)/(6)](https://img.qammunity.org/2020/formulas/mathematics/high-school/uhhd8zido7n7emcy61zakm58wcw09wc2ef.png)
![x=30](https://img.qammunity.org/2020/formulas/mathematics/middle-school/uw6o3xm0tea8s8hlq6f1vol2c22er6no3y.png)
The angles became,
![2x=2(30)=60](https://img.qammunity.org/2020/formulas/mathematics/high-school/cz78o8o5j5qflmzphjilnpvadtdxidx3ri.png)
![3x=3(30)=90](https://img.qammunity.org/2020/formulas/mathematics/high-school/u83brvq38f4cnti228pr0n05vjjrzrefe9.png)
![4x=4(30)=120](https://img.qammunity.org/2020/formulas/mathematics/high-school/31ahzrsye2m6pygow4hqr0yvvnuwkwi6w9.png)
We know that sum of all angles of quadrilateral is 360°,
Let the fourth angle be A,
![A+60+90+120=360](https://img.qammunity.org/2020/formulas/mathematics/high-school/ws0eiiy7672fh2ckoe00hem5xqdlhp38o9.png)
![A+270=360](https://img.qammunity.org/2020/formulas/mathematics/high-school/q0gz4y0f67h8l90894ayw1fljp5ikhxysm.png)
![A=360-270](https://img.qammunity.org/2020/formulas/mathematics/high-school/sp6etlfea3njzaesesqzd2lzv4xqbnzptb.png)
![A=90](https://img.qammunity.org/2020/formulas/mathematics/high-school/tgl7cf5lgkzdn6qp0m9euotneob2d66zfl.png)
Therefore, Among all the angles the largest angle of the quadrilateral is 120°.