Step-by-step explanation:
Mass of compounds = Moles of compound × Molecular mass of compound
a) Moles of LiCl = 2.345 mol
Molecular mass of LiCl = 42.5 g/mol
Mass of 2.345 moles of LiCl = 2.345 mol × 42.5 g/mol = 99.6625 g
b) Moles of acetylene = 0.0872 mol
Molecular mass of acetylene= 26 g/mol
Mass of 0.0872 moles acetylene= 0.0872 mol × 26 g/mol = 2.2672 g
c) Moles of sodium carbonate=
![3.3* 10^(-2)mol](https://img.qammunity.org/2020/formulas/chemistry/college/bu17mtowpzx2jxxwvhqhwjg1a39ie1htk8.png)
Molecular mass of sodium carbonate= 106 g/mol
Mass of
sodium carbonate
=
= 3.498 g
d) Moles of fructose =
![1.23* 10^3 mol](https://img.qammunity.org/2020/formulas/chemistry/college/63copssqjag68nih89l0k91zppza980nec.png)
Molecular mass fructose= 180 g/mol
Mass of
fructose
=
![1.23* 10^3mol* 180 g/mol = 221,400 g](https://img.qammunity.org/2020/formulas/chemistry/college/wwhwmano7ksdr0kr0sldpv665wprymadwv.png)
e) Moles of
![FeSO_4(H_2O)_7=0.5758 mol](https://img.qammunity.org/2020/formulas/chemistry/college/tgj7wd2w98esncabqwwd0oaevou9qwgcr9.png)
Molecular mass of
![FeSO_4(H_2O)_7 =278 g/mol](https://img.qammunity.org/2020/formulas/chemistry/college/p9co23o15iexqilrruzz8kgrlhbufb9hbq.png)
Mass of
fructose
=
![0.5758 mol* 278 g/mol= 160.0724 g](https://img.qammunity.org/2020/formulas/chemistry/college/k1mfg7teckt98k4zlmpowm6cfdwr75p6uc.png)