29.0k views
5 votes
M is a 2x2 singular matrix with tr M = 26. What is the value of the smaller eigenvalue of M? It is not necessary to know Mexactly.

1 Answer

3 votes

Answer:

0

Explanation:

Let the two eigen values are a and b

As we have given that trace of the matrix is 26

So a+b=26 (property of eigen value )

As the matrix is a singular matrix so the determinant of the matrix will be zero

So ab =0 ( property of the eigen values)

For ab =0 any one of the eigen value must be 0

If one eigen value will be zero then other will be 26

So the smaller eigen value will be zero

User Airs
by
5.8k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.